29 intermediate heat & thermodynamics MCQs with answers and explanations for MDCAT, FSc, PPSC preparation.
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Intermediate MDCAT FSc PPSC FPSC
Last updated: Oct 13, 2026
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Q1 of 29
The efficiency of a Carnot engine working between temperatures 400 K and 300 K is:
Correct Answer: Option A — 25%
Detailed Academic Explanation:
Efficiency η = 1 - T_c/T_h = 1 - 300/400 = 1 - 0.75 = 0.25 or 25%.
💡 Key Conceptual Anchor:
Heat & Thermodynamics
Q2 of 29
In an adiabatic process for an ideal gas, which relation holds true?
Correct Answer: Option B — PV^γ = constant
Detailed Academic Explanation:
For adiabatic process (no heat exchange), PV^γ = constant, where γ = Cp/Cv.
💡 Key Conceptual Anchor:
Heat & Thermodynamics
Q3 of 29
The ratio of specific heats (γ) for a diatomic gas at room temperature is:
Correct Answer: Option B — 1.40
Detailed Academic Explanation:
For diatomic gas: C_v = 5R/2, C_p = 7R/2, so γ = C_p/C_v = 7/5 = 1.40.
💡 Key Conceptual Anchor:
Heat & Thermodynamics
Q4 of 29
In an isothermal process for an ideal gas, the internal energy:
Correct Answer: Option C — Remains constant
Detailed Academic Explanation:
For ideal gas, internal energy depends only on temperature. In isothermal process, ΔT = 0, so ΔU = 0.
💡 Key Conceptual Anchor:
Heat & Thermodynamics
Q5 of 29
If the temperature of a black body is doubled, the energy radiated per second increases by a factor of:
Correct Answer: Option D — 16
Detailed Academic Explanation:
Stefan-Boltzmann law: P ∝ T⁴. If T doubles, P increases by 2⁴ = 16 times.
💡 Key Conceptual Anchor:
Heat & Thermodynamics
Q6 of 29
The efficiency of a heat engine cannot be 100% according to:
Correct Answer: Option C — Second law of thermodynamics
Detailed Academic Explanation:
Second law (Kelvin-Planck statement) states that no heat engine can convert all heat into work in a cyclic process.
💡 Key Conceptual Anchor:
Heat & Thermodynamics
Q7 of 29
The maximum efficiency of a Carnot engine working between 500 K and 300 K is:
Correct Answer: Option B — 40%
Detailed Academic Explanation:
η = 1 - T_c/T_h = 1 - 300/500 = 1 - 0.6 = 0.4 or 40%.
💡 Key Conceptual Anchor:
Heat & Thermodynamics
Q8 of 29
The efficiency of a Carnot engine working between temperatures T₁ and T₂ (T₁ > T₂) is:
Correct Answer: Option A — (T₁-T₂)/T₁
Detailed Academic Explanation:
Efficiency η = 1 - T₂/T₁ = (T₁-T₂)/T₁, where T₁ is source temperature and T₂ is sink temperature (in kelvin).
💡 Key Conceptual Anchor:
Heat & Thermodynamics
Q9 of 29
The root mean square speed of gas molecules is proportional to:
Correct Answer: Option A — √T
Detailed Academic Explanation:
From kinetic theory: vᵣₘₛ = √(3RT/M), so vᵣₘₛ ∝ √T, where T is absolute temperature and M is molar mass.
💡 Key Conceptual Anchor:
Heat & Thermodynamics
Q10 of 29
The ratio of specific heats (γ = Cp/Cv) for a diatomic gas is:
Correct Answer: Option B — 1.40
Detailed Academic Explanation:
For diatomic gases (at room temperature): degrees of freedom f = 5 (3 translational + 2 rotational). γ = 1 + 2/f = 1 + 2/5 = 7/5 = 1.4.
💡 Key Conceptual Anchor:
Heat & Thermodynamics
Q11 of 29
The heat required to raise the temperature of 1 kg of water by 1°C is:
Correct Answer: Option B — 1 kilocalorie
Detailed Academic Explanation:
Specific heat capacity of water = 1 cal/g°C = 1 kcal/kg°C = 4186 J/kg°C ≈ 4200 J/kg°C. So 1 kg water requires 1 kilocalorie (or 4200 J) to raise temperature by 1°C.
💡 Key Conceptual Anchor:
Heat & Thermodynamics
Q12 of 29
The efficiency of a Carnot engine cannot be 100% because:
Correct Answer: Option D — Both B and C
Detailed Academic Explanation:
Efficiency η = 1 - T₂/T₁. For η = 1, either T₂ = 0 K (impossible per third law of thermodynamics) or T₁ = ∞ (impossible). Also, Kelvin-Planck statement of second law forbids 100% conversion of heat to work in cyclic process.
💡 Key Conceptual Anchor:
Heat & Thermodynamics
Q13 of 29
The ratio of specific heat at constant pressure to specific heat at constant volume for monoatomic gas is:
Correct Answer: Option C — 1.67
Detailed Academic Explanation:
For monoatomic gases: Cp = 5R/2, Cv = 3R/2, so γ = Cp/Cv = 5/3 ≈ 1.67.
💡 Key Conceptual Anchor:
Heat & Thermodynamics
Q14 of 29
The heat required to convert 1 kg ice at 0°C to water at 0°C is: (Latent heat of fusion of ice = 336 kJ/kg)
Correct Answer: Option D — 336000 J
Detailed Academic Explanation:
Q = mL = 1 × 336,000 = 336,000 J = 336 kJ.
💡 Key Conceptual Anchor:
Heat & Thermodynamics
Q15 of 29
The efficiency of a Carnot engine working between 500 K and 300 K is:
Correct Answer: Option B — 40%
Detailed Academic Explanation:
Efficiency η = 1 - T_c/T_h = 1 - 300/500 = 1 - 0.6 = 0.4 or 40%.
💡 Key Conceptual Anchor:
Heat & Thermodynamics
Q16 of 29
The ratio of specific heats (γ) for a monatomic ideal gas is:
Correct Answer: Option C — 1.67
Detailed Academic Explanation:
For monatomic gas: C_v = 3R/2, C_p = 5R/2, so γ = C_p/C_v = 5/3 ≈ 1.67.
💡 Key Conceptual Anchor:
Heat & Thermodynamics
Q17 of 29
The process by which unstable nucleus emits radiation to become more stable is called:
Correct Answer: Option B — Radioactivity
Detailed Academic Explanation:
Radioactivity (discovered by Becquerel, 1896) is spontaneous emission of α, β, or γ radiation by unstable nuclei.
💡 Key Conceptual Anchor:
Heat & Thermodynamics
Q18 of 29
The greenhouse effect is caused primarily by absorption of infrared radiation by:
Correct Answer: Option C — Carbon dioxide and water vapor
Detailed Academic Explanation:
CO₂ and H₂O vapor absorb infrared radiation emitted by Earth's surface, trapping heat in atmosphere.
💡 Key Conceptual Anchor:
Heat & Thermodynamics
Q19 of 29
The ozone layer absorbs most of:
Correct Answer: Option C — Ultraviolet radiation
Detailed Academic Explanation:
Ozone (O₃) in stratosphere absorbs harmful UV-B and UV-C radiation (200-310 nm), protecting life on Earth.
💡 Key Conceptual Anchor:
Heat & Thermodynamics
Q20 of 29
In an isothermal process for an ideal gas:
Correct Answer: Option A — Temperature remains constant
Detailed Academic Explanation:
'Isothermal' means 'at constant temperature'. In an isothermal process, the temperature of the system remains constant throughout. For an ideal gas, this implies that internal energy (ΔU = 0) does not change.
💡 Key Conceptual Anchor:
Heat & Thermodynamics
Q21 of 29
A heat engine converts:
Correct Answer: Option B — Heat into work
Detailed Academic Explanation:
A heat engine is a device that takes in heat from a hot reservoir, converts part of it into useful work (like moving a piston), and rejects the remaining waste heat to a cold reservoir.
💡 Key Conceptual Anchor:
Heat & Thermodynamics
Q22 of 29
The temperature at which the Celsius and Fahrenheit scales read the same value is:
Correct Answer: Option B — -40°
Detailed Academic Explanation:
To find where °C = °F, use the conversion formula: F = (9/5)C + 32. Substitute F = C: C = (9/5)C + 32. Solving gives C - (9/5)C = 32 => (-4/5)C = 32 => C = -40°. So, -40°C = -40°F.
💡 Key Conceptual Anchor:
Heat & Thermodynamics
Q23 of 29
In an adiabatic process, which of the following remains constant?
Correct Answer: Option D — Total heat of the system
Detailed Academic Explanation:
An adiabatic process is one in which no heat is exchanged between the system and its surroundings (Q = 0). This does not mean temperature is constant (that's isothermal). The total heat content is not a defined state function.
💡 Key Conceptual Anchor:
Heat & Thermodynamics
Q24 of 29
The efficiency of a Carnot engine depends only on:
Correct Answer: Option B — The temperatures of the source and sink
Detailed Academic Explanation:
Carnot's theorem states that the efficiency of a Carnot engine (the most efficient heat engine) depends solely on the absolute temperatures of the hot reservoir (T₁) and the cold reservoir (T₂): η = 1 - T₂/T₁.
💡 Key Conceptual Anchor:
Heat & Thermodynamics
Q25 of 29
At absolute zero temperature, a pure crystalline solid has:
Correct Answer: Option B — Zero entropy
Detailed Academic Explanation:
The Third Law of Thermodynamics states that the entropy of a perfect crystal at absolute zero temperature is exactly zero. At 0 K, there is only one possible microstate (perfect order), so entropy S = k ln W = k ln 1 = 0.
💡 Key Conceptual Anchor:
Heat & Thermodynamics
Q26 of 29
The law that relates the pressure, volume, and temperature of an ideal gas is called:
Correct Answer: Option C — Ideal gas law
Detailed Academic Explanation:
The ideal gas law (PV = nRT) combines Boyle's law (P ∝ 1/V), Charles's law (V ∝ T), and Avogadro's law (V ∝ n) into a single equation of state for an ideal gas.
💡 Key Conceptual Anchor:
Heat & Thermodynamics
Q27 of 29
If the absolute temperature of a black body is doubled, the total energy radiated per second per unit area becomes:
Correct Answer: Option D — Sixteen times
Detailed Academic Explanation:
According to Stefan-Boltzmann law, the total energy radiated per second per unit area (E) is proportional to the fourth power of its absolute temperature: E = σT⁴. If T becomes 2T, then E becomes (2)⁴ = 16 times.
💡 Key Conceptual Anchor:
Heat & Thermodynamics
Q28 of 29
In a nuclear reactor, the function of the moderator is to:
Correct Answer: Option B — Slow down fast neutrons
Detailed Academic Explanation:
The moderator (like graphite or heavy water) slows down the fast neutrons produced in fission to thermal neutrons. Thermal neutrons are more effective at causing further fission in U-235.
💡 Key Conceptual Anchor:
Heat & Thermodynamics
Q29 of 29
The specific heat capacity of a substance is:
Correct Answer: Option C — Heat required to raise temperature of 1 kg by 1 K
Detailed Academic Explanation:
Specific heat capacity is defined as the amount of heat energy required to raise the temperature of a unit mass (1 kg) of a substance by one degree kelvin (or one degree Celsius).
💡 Key Conceptual Anchor:
Heat & Thermodynamics
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