Electricity & Magnetism — Part 2: 40 MCQs with Explanations
40 intermediate electricity & magnetism MCQs with answers and explanations for MDCAT, FSc, PPSC preparation.
40
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Intermediate
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4
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60
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Intermediate MDCAT FSc PPSC FPSC
Last updated: Oct 13, 2026
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Q1 of 40
The antiparticle of electron is:
Correct Answer: Option C — Positron
Detailed Academic Explanation:
Positron (e⁺) has same mass as electron but positive charge. Discovered by Anderson in cosmic rays (1932).
💡 Key Conceptual Anchor:
Electricity & Magnetism
Q2 of 40
The ionizing power is maximum for:
Correct Answer: Option A — Alpha particles
Detailed Academic Explanation:
Ionizing power: α > β > γ. Alpha has large mass and charge, creates dense ionization along short path.
💡 Key Conceptual Anchor:
Electricity & Magnetism
Q3 of 40
The reactance of pure inductor in AC circuit is:
Correct Answer: Option A — ωL
Detailed Academic Explanation:
Inductive reactance X_L = ωL = 2πfL. Current lags voltage by 90°.
💡 Key Conceptual Anchor:
Electricity & Magnetism
Q4 of 40
The reactance of pure capacitor in AC circuit is:
Correct Answer: Option B — 1/ωC
Detailed Academic Explanation:
Capacitive reactance X_C = 1/ωC = 1/(2πfC). Current leads voltage by 90°.
💡 Key Conceptual Anchor:
Electricity & Magnetism
Q5 of 40
The average power in AC circuit is given by:
Correct Answer: Option B — VI cosφ
Detailed Academic Explanation:
Average power P_avg = V_rms I_rms cosφ, where φ = phase angle between voltage and current. cosφ = power factor.
💡 Key Conceptual Anchor:
Electricity & Magnetism
Q6 of 40
The rms value of AC voltage V = V₀ sinωt is:
Correct Answer: Option B — V₀/√2
Detailed Academic Explanation:
V_rms = V₀/√2 for sinusoidal AC. Similarly I_rms = I₀/√2.
💡 Key Conceptual Anchor:
Electricity & Magnetism
Q7 of 40
The principle of transformer is based on:
Correct Answer: Option B — Mutual induction
Detailed Academic Explanation:
Transformer works on mutual induction between primary and secondary coils linked by changing magnetic flux.
💡 Key Conceptual Anchor:
Electricity & Magnetism
Q8 of 40
For step-up transformer:
Correct Answer: Option A — N_s > N_p
Detailed Academic Explanation:
Step-up transformer increases voltage: V_s/V_p = N_s/N_p > 1, so N_s > N_p. Current decreases proportionally (ignoring losses).
💡 Key Conceptual Anchor:
Electricity & Magnetism
Q9 of 40
The efficiency of practical transformer is typically:
Correct Answer: Option D — 95-99%
Detailed Academic Explanation:
Large power transformers have efficiency 95-99% due to low losses (copper, iron, hysteresis, eddy current).
💡 Key Conceptual Anchor:
Electricity & Magnetism
Q10 of 40
The energy stored in magnetic field per unit volume is:
Correct Answer: Option A — B²/2μ₀
Detailed Academic Explanation:
Energy density u_B = B²/2μ₀ in vacuum (analogous to u_E = ½ε₀E² for electric field).
💡 Key Conceptual Anchor:
Electricity & Magnetism
Q11 of 40
The displacement current was introduced by Maxwell to:
Correct Answer: Option D — All of the above
Detailed Academic Explanation:
Displacement current I_d = ε₀(dΦ_E/dt) completes circuit during capacitor charging and modifies Ampere's law to Ampere-Maxwell law.
💡 Key Conceptual Anchor:
Electricity & Magnetism
Q12 of 40
Which of the following rays are deflected by an electric field?
Correct Answer: Option C — Cathode rays
Detailed Academic Explanation:
Cathode rays are streams of electrons, which are negatively charged particles. Therefore, they are deflected by both electric and magnetic fields. X-rays, gamma rays, and neutrons are uncharged and are not deflected.
💡 Key Conceptual Anchor:
Electricity & Magnetism
Q13 of 40
If the charge on a capacitor is doubled, its capacitance:
Correct Answer: Option C — Remains the same
Detailed Academic Explanation:
Capacitance (C) is a geometric property of the capacitor (C = ε₀A/d). It depends on the area of plates and the distance between them, not on the charge (Q) or voltage (V). C = Q/V, but if Q is doubled, V also doubles, keeping C constant.
💡 Key Conceptual Anchor:
Electricity & Magnetism
Q14 of 40
The electric field lines point:
Correct Answer: Option B — From higher potential to lower potential
Detailed Academic Explanation:
By convention, electric field lines start at positive charges (high potential) and end at negative charges (low potential). They point in the direction of decreasing electric potential.
💡 Key Conceptual Anchor:
Electricity & Magnetism
Q15 of 40
Three capacitors of equal capacitance C are connected in parallel. The equivalent capacitance is:
Correct Answer: Option B — 3C
Detailed Academic Explanation:
When capacitors are connected in parallel, the equivalent capacitance is the sum of individual capacitances. For three capacitors each of value C, C_eq = C + C + C = 3C.
💡 Key Conceptual Anchor:
Electricity & Magnetism
Q16 of 40
According to Ohm's law, the current through a conductor is directly proportional to:
Correct Answer: Option B — Potential difference
Detailed Academic Explanation:
Ohm's law states that at constant temperature, the current (I) flowing through a conductor is directly proportional to the potential difference (V) applied across its ends. V ∝ I, or V = IR.
💡 Key Conceptual Anchor:
Electricity & Magnetism
Q17 of 40
An ammeter is always connected in:
Correct Answer: Option B — Series
Detailed Academic Explanation:
An ammeter measures current. To measure the current flowing through a branch, the ammeter must be connected in series so that the entire current of that branch passes through it. It has very low resistance.
💡 Key Conceptual Anchor:
Electricity & Magnetism
Q18 of 40
The heating effect of current is given by:
Correct Answer: Option D — All of these
Detailed Academic Explanation:
All three formulas are equivalent and can be derived from Joule's law of heating (H = I²Rt) by using Ohm's law V = IR. H = I²Rt = (V/R)² R t = V²t/R = VIt.
💡 Key Conceptual Anchor:
Electricity & Magnetism
Q19 of 40
The mutual inductance between two coils depends on:
Correct Answer: Option C — Their geometry and separation
Detailed Academic Explanation:
Mutual inductance (M) is a measure of the ability of one coil to induce an EMF in another. It depends on the geometry (size, shape, number of turns) of the coils, their relative positions, and the magnetic properties of the core material.
💡 Key Conceptual Anchor:
Electricity & Magnetism
Q20 of 40
The peak value of an AC voltage is 311 V. Its RMS value is approximately:
Correct Answer: Option B — 220 V
Detailed Academic Explanation:
The RMS value of a sinusoidal AC is related to the peak value by V_rms = V_peak / √2. √2 ≈ 1.414. So, V_rms = 311 / 1.414 ≈ 220 V.
💡 Key Conceptual Anchor:
Electricity & Magnetism
Q21 of 40
In a transformer, if the number of turns in the primary is less than in the secondary, it is a:
Correct Answer: Option B — Step-up transformer
Detailed Academic Explanation:
A transformer works on the principle of mutual induction. The voltage ratio is equal to the turns ratio: V_s/V_p = N_s/N_p. If N_s > N_p, then V_s > V_p, so it is a step-up transformer.
💡 Key Conceptual Anchor:
Electricity & Magnetism
Q22 of 40
The impedance of an AC circuit containing only a pure capacitor is:
Correct Answer: Option C — 1/ωC
Detailed Academic Explanation:
Impedance (Z) is the total opposition to current in an AC circuit. For a pure capacitor, the opposition is called capacitive reactance, given by Xc = 1/(ωC) = 1/(2πfC).
💡 Key Conceptual Anchor:
Electricity & Magnetism
Q23 of 40
The internal resistance of an ideal voltmeter is:
Correct Answer: Option B — Infinite
Detailed Academic Explanation:
An ideal voltmeter should not draw any current from the circuit it is measuring. To achieve this, it must have infinite resistance so that it acts as an open circuit and measures the true potential difference.
💡 Key Conceptual Anchor:
Electricity & Magnetism
Q24 of 40
Two parallel plate capacitors of capacitance C and 2C are connected in series. The equivalent capacitance is:
Correct Answer: Option B — 2C/3
Detailed Academic Explanation:
For capacitors in series, 1/C_eq = 1/C₁ + 1/C₂. So, 1/C_eq = 1/C + 1/(2C) = (2+1)/(2C) = 3/(2C). Therefore, C_eq = 2C/3.
💡 Key Conceptual Anchor:
Electricity & Magnetism
Q25 of 40
A 10 Ω resistor carries a current of 2 A. The power dissipated in it is:
Correct Answer: Option C — 40 W
Detailed Academic Explanation:
Power dissipated in a resistor can be calculated using P = I²R. Here, I = 2 A and R = 10 Ω. So, P = (2)² × 10 = 4 × 10 = 40 W.
💡 Key Conceptual Anchor:
Electricity & Magnetism
Q26 of 40
The time constant of an RC circuit is given by:
Correct Answer: Option C — RC
Detailed Academic Explanation:
The time constant (τ) of an RC circuit is the time required to charge the capacitor to approximately 63.2% of its final value (or discharge to 36.8%). It is given by the product of resistance and capacitance, τ = RC.
💡 Key Conceptual Anchor:
Electricity & Magnetism
Q27 of 40
Alternating current (AC) cannot be measured by DC ammeter because:
Correct Answer: Option B — AC changes direction
Detailed Academic Explanation:
A DC ammeter measures average current. The average value of a symmetrical AC over a complete cycle is zero because it alternates between positive and negative values. Hence, a DC ammeter will show zero reading.
💡 Key Conceptual Anchor:
Electricity & Magnetism
Q28 of 40
Which of the following gates is known as a universal gate?
Correct Answer: Option D — NAND
Detailed Academic Explanation:
NAND and NOR gates are called universal gates because any basic logic gate (AND, OR, NOT) and any complex logic circuit can be implemented using only NAND gates (or only NOR gates).
💡 Key Conceptual Anchor:
Electricity & Magnetism
Q29 of 40
Magnetic flux is a:
Correct Answer: Option A — Scalar quantity
Detailed Academic Explanation:
Magnetic flux (Φ = B·A = BA cos θ) is defined as the dot product of the magnetic field vector (B) and the area vector (A). The result of a dot product is a scalar quantity.
💡 Key Conceptual Anchor:
Electricity & Magnetism
Q30 of 40
In a purely inductive AC circuit, the current:
Correct Answer: Option A — Lags behind voltage by 90°
Detailed Academic Explanation:
In a pure inductor, the voltage across the inductor leads the current by 90° (or the current lags the voltage by 90°). This is because the induced EMF opposes the change in current.
💡 Key Conceptual Anchor:
Electricity & Magnetism
Q31 of 40
Which of the following statements about a PN junction diode is correct?
Correct Answer: Option B — It allows current in one direction only
Detailed Academic Explanation:
A PN junction diode is a semiconductor device that allows current to flow easily in one direction (forward bias) and blocks current in the opposite direction (reverse bias). It acts as a rectifier.
💡 Key Conceptual Anchor:
Electricity & Magnetism
Q32 of 40
The conductivity of a semiconductor:
Correct Answer: Option A — Increases with an increase in temperature
Detailed Academic Explanation:
Semiconductors have a negative temperature coefficient of resistance. As temperature increases, more covalent bonds break, generating more free electrons and holes. This increases the number of charge carriers, thereby increasing conductivity.
💡 Key Conceptual Anchor:
Electricity & Magnetism
Q33 of 40
The unit of reactance is the same as that of:
Correct Answer: Option A — Resistance
Detailed Academic Explanation:
Reactance (inductive XL or capacitive XC) is the opposition to current in an AC circuit due to inductance or capacitance. It is measured in ohms (Ω), which is the same unit as resistance.
💡 Key Conceptual Anchor:
Electricity & Magnetism
Q34 of 40
A wire of resistance R is stretched to double its length. Its new resistance will be:
Correct Answer: Option D — 4R
Detailed Academic Explanation:
Resistance R = ρL/A. When length is doubled (L' = 2L), volume remains constant, so A' = A/2. New resistance R' = ρ(2L) / (A/2) = ρL/A × 4 = 4R.
💡 Key Conceptual Anchor:
Electricity & Magnetism
Q35 of 40
A galvanometer can be converted into a voltmeter by connecting a:
Correct Answer: Option B — High resistance in series
Detailed Academic Explanation:
To convert a galvanometer into a voltmeter, a high resistance is connected in series with it. This limits the current through the galvanometer and allows the combination to measure large potential differences.
💡 Key Conceptual Anchor:
Electricity & Magnetism
Q36 of 40
A galvanometer of resistance 50 Ω gives a full-scale deflection for a current of 5 mA. To convert it into a voltmeter of range 0-5 V, the required series resistance is:
Correct Answer: Option B — 950 Ω
Detailed Academic Explanation:
For a voltmeter, V = Ig(G + R). So, 5 = (5 × 10⁻³)(50 + R). This gives 1000 = 50 + R, so R = 1000 - 50 = 950 Ω.
💡 Key Conceptual Anchor:
Electricity & Magnetism
Q37 of 40
A point charge Q is placed at the center of a spherical Gaussian surface. The electric flux through the surface will change if:
Correct Answer: Option D — The point charge is replaced by a charge 2Q
Detailed Academic Explanation:
According to Gauss's law, the net flux through a closed surface is proportional to the charge enclosed (Φ = Q/ε₀). Changing the shape (cube instead of sphere) or moving the charge inside doesn't change the total enclosed charge. Placing a charge outside doesn't change enclosed charge. Only changing Q to 2Q changes the enclosed charge and thus the flux.
💡 Key Conceptual Anchor:
Electricity & Magnetism
Q38 of 40
In a step-up transformer, the current in the secondary coil is:
Correct Answer: Option B — Less than in the primary
Detailed Academic Explanation:
For an ideal transformer, power input = power output, so VpIp = VsIs. In a step-up transformer, Vs > Vp. Therefore, to maintain equal power, Is must be less than Ip.
💡 Key Conceptual Anchor:
Electricity & Magnetism
Q39 of 40
A galvanometer of resistance 100 Ω gives a full-scale deflection for a current of 1 mA. The shunt resistance required to convert it into an ammeter of range 0-10 A is approximately:
Correct Answer: Option A — 0.01 Ω
Detailed Academic Explanation:
For an ammeter, S = IgG / (I - Ig) = (0.001 A × 100 Ω) / (10 A - 0.001 A) ≈ 0.1 / 9.999 ≈ 0.01 Ω.
💡 Key Conceptual Anchor:
Electricity & Magnetism
Q40 of 40
A current of 1 A flows through a conductor when a potential difference of 2 V is applied. Its resistance is:
Correct Answer: Option A — 2 Ω
Detailed Academic Explanation:
Ohm's law: V = IR, so R = V/I = 2 V / 1 A = 2 Ω.
💡 Key Conceptual Anchor:
Electricity & Magnetism
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