Mechanics & Motion — Part 4: 32 MCQs with Explanations
32 basic mechanics & motion MCQs with answers and explanations for MDCAT, FSc, PPSC preparation.
32
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Basic
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4
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48
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Basic MDCAT FSc PPSC FPSC
Last updated: Oct 13, 2026
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Q1 of 32
A person standing on a frictionless horizontal surface throws a ball. The person will:
Correct Answer: Option C — Move opposite to the direction of the throw
Detailed Academic Explanation:
This is based on Newton's third law and conservation of momentum. When the person exerts a force on the ball to throw it forward, the ball exerts an equal and opposite force on the person, pushing them backward.
💡 Key Conceptual Anchor:
Mechanics & Motion
Q2 of 32
A girl is sitting on a swing. Another girl sits by her side. The time period of the swing:
Correct Answer: Option C — Remains the same
Detailed Academic Explanation:
The time period of a simple pendulum (or swing) T = 2π√(L/g) depends only on its length (L) and the acceleration due to gravity (g). It is independent of the mass of the bob. Adding more mass does not change the time period.
💡 Key Conceptual Anchor:
Mechanics & Motion
Q3 of 32
If a motorcyclist doubles his speed on a circular turn of the same radius, the centripetal force required becomes:
Correct Answer: Option C — Four times
Detailed Academic Explanation:
Centripetal force F_c = mv²/r. For a constant mass (m) and radius (r), F_c ∝ v². If the speed (v) is doubled, the force becomes (2)² = 4 times the original force.
💡 Key Conceptual Anchor:
Mechanics & Motion
Q4 of 32
The value of Boltzmann's constant (k) is:
Correct Answer: Option A — 1.38 × 10⁻²³ J/K
Detailed Academic Explanation:
Boltzmann's constant (k) relates the average kinetic energy of particles in a gas with the temperature. Its value is 1.38 × 10⁻²³ joules per kelvin (J/K).
💡 Key Conceptual Anchor:
Mechanics & Motion
Q5 of 32
During a phase change (e.g., ice melting at 0°C), the temperature of the substance:
Correct Answer: Option C — Remains constant
Detailed Academic Explanation:
During a phase transition, the heat supplied (latent heat) is used to overcome the intermolecular forces to change the phase of the substance, not to increase the average kinetic energy of the molecules. Therefore, the temperature remains constant.
💡 Key Conceptual Anchor:
Mechanics & Motion
Q6 of 32
Which of the following properties of a wave is independent of the others?
Correct Answer: Option D — Amplitude
Detailed Academic Explanation:
Amplitude is a measure of the energy carried by the wave and is independent of the wave's frequency, wavelength, or velocity. The other three are related by the equation v = fλ.
💡 Key Conceptual Anchor:
Mechanics & Motion
Q7 of 32
The S.I. unit of momentum is:
Correct Answer: Option B — N·s
Detailed Academic Explanation:
Momentum (p = mv) has units of kg m/s. A Newton-second (N·s) is equivalent to (kg m/s²) × s = kg m/s, so it is the same unit.
💡 Key Conceptual Anchor:
Mechanics & Motion
Q8 of 32
In the equation F = ma, 'm' represents:
Correct Answer: Option B — Mass
Detailed Academic Explanation:
In Newton's second law of motion, F = ma, 'm' stands for the inertial mass of the object, which is a measure of its resistance to acceleration.
💡 Key Conceptual Anchor:
Mechanics & Motion
Q9 of 32
The value of 'g' is minimum at:
Correct Answer: Option B — The equator
Detailed Academic Explanation:
The value of 'g' is minimum at the equator. This is due to two reasons: the Earth's radius is larger at the equator (centrifugal force from rotation also reduces effective g), and the centrifugal force due to Earth's rotation is maximum at the equator.
💡 Key Conceptual Anchor:
Mechanics & Motion
Q10 of 32
X-rays are produced when:
Correct Answer: Option A — Electrons strike a metal target
Detailed Academic Explanation:
X-rays are produced in an X-ray tube when high-speed electrons are accelerated and suddenly stopped by striking a metal target (usually tungsten or copper). The kinetic energy of the electrons is converted into X-ray radiation.
💡 Key Conceptual Anchor:
Mechanics & Motion
Q11 of 32
A 5 kg mass is moving with a constant velocity of 2 m/s. The net force acting on it is:
Correct Answer: Option C — 0 N
Detailed Academic Explanation:
According to Newton's first law, if a body is moving with constant velocity (no acceleration), the net external force acting on it must be zero.
💡 Key Conceptual Anchor:
Mechanics & Motion
Q12 of 32
The property of a body due to which it opposes any change in its state of rest or uniform motion is called:
Correct Answer: Option C — Inertia
Detailed Academic Explanation:
Inertia is the natural tendency of an object to resist changes in its state of motion. This property is quantified by its mass.
💡 Key Conceptual Anchor:
Mechanics & Motion
Q13 of 32
Which of the following is an example of a non-conservative force?
Correct Answer: Option D — Friction
Detailed Academic Explanation:
A force is non-conservative if the work done by it depends on the path taken. Friction is a classic example, as longer paths result in more negative work done. Work done by conservative forces (gravity, spring) is path-independent.
💡 Key Conceptual Anchor:
Mechanics & Motion
Q14 of 32
A 0.5 kg ball is thrown upwards with a speed of 20 m/s. Its kinetic energy at the highest point is:
Correct Answer: Option C — 0 J
Detailed Academic Explanation:
At the highest point, the vertical velocity of the ball becomes zero. Kinetic energy (KE = 1/2 mv²) is proportional to the square of velocity. Since v=0, the KE at that instant is zero.
💡 Key Conceptual Anchor:
Mechanics & Motion
Q15 of 32
A body moving with a constant speed in a circle:
Correct Answer: Option C — Has a centripetal acceleration
Detailed Academic Explanation:
Even with constant speed, the direction of velocity changes continuously. This change in direction constitutes an acceleration directed towards the center of the circle, called centripetal acceleration.
💡 Key Conceptual Anchor:
Mechanics & Motion
Q16 of 32
The mass of a body:
Correct Answer: Option B — Is constant everywhere
Detailed Academic Explanation:
Mass is a fundamental property of matter and is a measure of its inertia. It is a scalar quantity that remains constant everywhere, regardless of location. Weight varies due to changes in 'g'.
💡 Key Conceptual Anchor:
Mechanics & Motion
Q17 of 32
The de Broglie wavelength associated with a moving particle is inversely proportional to its:
Correct Answer: Option D — Momentum
Detailed Academic Explanation:
The de Broglie hypothesis states that every moving particle has a wave-like nature. Its wavelength λ is given by λ = h/p, where h is Planck's constant and p is the momentum of the particle. Therefore, λ ∝ 1/p.
💡 Key Conceptual Anchor:
Mechanics & Motion
Q18 of 32
A force of 10 N acts on a body for 5 seconds. The impulse is:
Correct Answer: Option C — 50 Ns
Detailed Academic Explanation:
Impulse = Force × time = 10 N × 5 s = 50 Ns.
💡 Key Conceptual Anchor:
Mechanics & Motion
Q19 of 32
The rest mass of a photon is:
Correct Answer: Option A — Zero
Detailed Academic Explanation:
A photon is a massless particle. It always travels at the speed of light in vacuum and has zero rest mass. Its energy and momentum are carried by its frequency, not its mass.
💡 Key Conceptual Anchor:
Mechanics & Motion
Q20 of 32
If the distance between two bodies is increased by a factor of 4, the gravitational force between them becomes:
Correct Answer: Option D — 1/16 times
Detailed Academic Explanation:
According to Newton's law of gravitation, F ∝ 1/r². If r becomes 4r, then r² becomes 16r². Therefore, the new force F' ∝ 1/(16r²) = (1/16) × (1/r²). So, the force becomes one-sixteenth of the original.
💡 Key Conceptual Anchor:
Mechanics & Motion
Q21 of 32
A body of mass m is moving in a circle of radius r with constant speed v. The work done by the centripetal force in half a revolution is:
Correct Answer: Option C — 0
Detailed Academic Explanation:
The centripetal force is always perpendicular to the instantaneous displacement of the body. Work done W = F·d = F d cos 90° = 0. This is true for any displacement along the circular path.
💡 Key Conceptual Anchor:
Mechanics & Motion
Q22 of 32
The horizontal range of a projectile is the same for which two angles of projection?
Correct Answer: Option A — 30° and 60°
Detailed Academic Explanation:
The range R = (u² sin 2θ)/g. Since sin(2θ) = sin(180° - 2θ), the range is the same for complementary angles (θ and 90° - θ). 30° and 60° are complementary (30+60=90).
💡 Key Conceptual Anchor:
Mechanics & Motion
Q23 of 32
The escape velocity from the surface of a planet does not depend upon:
Correct Answer: Option C — Mass of the body
Detailed Academic Explanation:
Escape velocity v_esc = √(2GM/R). It depends on the mass (M) and radius (R) of the planet, and the gravitational constant (G). It is independent of the mass of the body trying to escape.
💡 Key Conceptual Anchor:
Mechanics & Motion
Q24 of 32
A ball is thrown vertically upwards with a velocity of 20 m/s. The maximum height reached is (g=10 m/s²):
Correct Answer: Option B — 20 m
Detailed Academic Explanation:
At maximum height, final velocity v=0. Using v² = u² - 2gh, we get 0 = (20)² - 2×10×h => 400 = 20h => h = 20 m.
💡 Key Conceptual Anchor:
Mechanics & Motion
Q25 of 32
If the speed of a car is halved, the stopping distance under the same braking force becomes:
Correct Answer: Option B — One-fourth
Detailed Academic Explanation:
Stopping distance is proportional to the square of the initial speed (from v² = 2as). If speed is halved (v/2), the distance becomes (1/2)² = 1/4 times the original distance.
💡 Key Conceptual Anchor:
Mechanics & Motion
Q26 of 32
Which of the following is the correct expression for the orbital velocity of a satellite near the Earth's surface?
Correct Answer: Option A — √(gR)
Detailed Academic Explanation:
Orbital velocity v₀ = √(GM/R). Since g = GM/R², we have GM = gR². Substituting, v₀ = √(gR²/R) = √(gR). Escape velocity is √(2gR).
💡 Key Conceptual Anchor:
Mechanics & Motion
Q27 of 32
A particle is executing SHM with amplitude A. At what displacement from the mean position is its energy half kinetic and half potential?
Correct Answer: Option B — A/√2
Detailed Academic Explanation:
Total energy E = (1/2)kA². Potential energy U = (1/2)kx². For U = E/2, we have (1/2)kx² = (1/2) × (1/2)kA² => x² = A²/2 => x = A/√2.
💡 Key Conceptual Anchor:
Mechanics & Motion
Q28 of 32
A 10 kg mass is lifted to a height of 5 m. The work done against gravity is (g=10 m/s²):
Correct Answer: Option C — 500 J
Detailed Academic Explanation:
Work done against gravity = mgh = 10 kg × 10 m/s² × 5 m = 500 J.
💡 Key Conceptual Anchor:
Mechanics & Motion
Q29 of 32
If the momentum of a body is increased by 50%, its kinetic energy will increase by:
Correct Answer: Option C — 125%
Detailed Academic Explanation:
Let initial p = p. New p' = 1.5p. Initial K = p²/2m. New K' = (1.5p)²/2m = 2.25p²/2m = 2.25K. % increase = (2.25-1)×100 = 125%.
💡 Key Conceptual Anchor:
Mechanics & Motion
Q30 of 32
A bullet is fired from a gun. The ratio of the kinetic energy of the bullet to that of the gun (recoil) is:
Correct Answer: Option C — Inversely proportional to the ratio of their masses
A body of mass m is moving in a vertical circle of radius r with critical speed. The tension in the string at the highest point is:
Correct Answer: Option B — 0
Detailed Academic Explanation:
At the highest point for critical speed (minimum speed to complete the circle), the centripetal force is provided entirely by the weight of the body. The tension (T) in the string becomes zero. mv²/r = mg.
💡 Key Conceptual Anchor:
Mechanics & Motion
Q32 of 32
A force is conservative if the work done by it:
Correct Answer: Option B — Is zero for a closed loop
Detailed Academic Explanation:
A conservative force has the property that the work done by it around any closed path is zero. Equivalently, the work done is independent of the path and depends only on the initial and final positions.
💡 Key Conceptual Anchor:
Mechanics & Motion
💡 How to Use These MCQs
Self-Assessment: Test your current knowledge level before studying.
Learning Aid: Read explanations carefully to understand concepts, not just memorize answers.
Revision Tool: Review these questions periodically before exams.
Time Management: Practice answering within time limits to improve speed.